Question

• A. Ph-HC=CH-Ph
• B.
• C.
• D.

Answer 1

The correct option is B

You'll study later that $R-\stackrel{\stackrel{O}{||}}{C}-CH\underset{O^{\circ }C}{\overset{PC{l}_5}{\to }}$

Product A is shown above.

$A\underset{\left(2\right)H^{+}}{\overset{\left(1\right)3eqNaN{H}_{2}mineral}{\to }}\begin{array}{c}B\\ 46.1\end{array}$

$NaN{H}_2$ in mineral oil $\Rightarrow$ dehydrohalogenation.

3eq of $NaN{H}_2$ is ud $\Rightarrow$ Terminal alkynes is the intended product

$R-C\equiv CH\underset{N{H}_3}{\overset{NaN{H}_2}{\to }}R-C\equiv C^{-}N{a}^{+}$

The above reaction uses up $NaN{H}_2$ intended for dehydrohalogenation.

Hence $3NaN{H}_2$.

Obviously