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Question

Ph−NO2X−→C6H5−NH−NH−C6H5

Then X is:

A
Zn+NH4Cl
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B
Sn+HCl
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C
Zn+KOH
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D
LiAlH4
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Solution

The correct option is C Zn+KOH
When nitrobenzene is reduced with zinc in presence of alcoholic KOH, hydrazobenzene is formed.

2C6H5NO2+Zn Powderalcoholic KOH−−−−−−−−C6H5NHNHC6H5hydrazobenzene

Hence, option C is correct.

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