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Salt of Weak Acid and Strong Base

pH of 0.001...

Question

$p H$ of $0.001 M$ solution of $Z n {C l}_{2}$ is : ${Z n}^{2 +} + H_{2} O ⇌ Z n {(O H)}^{+} + H^{+}$
Use : [ $K_{a} = 1.0 \times 10^{- 9}$ ]

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Solution

${Z n}^{2 +} + H_{2} O ⇌ Z n {(O H)}^{+} + H^{+}$

$[H^{+}] = c \cdot h = c \sqrt{\frac{K_{a}}{c}} = \sqrt{K_{a} \cdot c} = \sqrt{10^{- 9} \times 0.001} = 10^{- 6} M$
$∴ p H = - l o g [H^{+}] = - l o g [10^{- 6}] = 6$

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