PH of 0-005 M HCOOH - K a -2- 10 -4 - is equals to-

The correct option is C 5 Concentration of HCOOH , C=0.005M K _ a =2× 10 ^ 4 pH=1/2 pK _ a 1/2logC #160; #160; #160; #16 ...

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pH of a Solution

pH of 0.005...

Question

$p H$ of $0.005 M$ $H C O O H$ $[K_{a} = 2 \times 10^{- 4}]$ is equals to:

3

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Solution

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Similar questions

0.005 M

H C O O H

[K_{a} = 2 \times 10^{- 4}]

m o l e s

H C O O N a

1 L

0.1 M

H C O O H

p H

3.4

K_{a}

H C O O H = 2 \times 10^{- 4}

5 \times 10^{- 3} M

K_{a} (H C O O H) = 2 \times 10^{- 4}

0.05 mol d m^{- 3}

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0.250 m o l d m^{- 3}

H C O O^{-} N a^{+} .

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1.78 \times 10^{- 4} .

l o g 1.78 = 0.250, l o g 5 = 0.699

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0.5

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(K_{a} = 1.8 \times 10^{- 4})

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