If you look at the formula of the compound there are two OH- for every Ca2+. So 0.005 M Ca(OH)2 gives a solution 0.010 M in OH- .
Now all you need to do is to take the negative log of this number and that would be your pOH.
-log(0.01) = 2 = pOH
pH + pOH = 14
According to this statement, your pH would be 12.