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Molarity

pH of 0.01 M ...

Question

pH of 0.01 M $H S^{-}$ will be -

A

=

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B

=

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C

=

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D

=

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Solution

The correct option is C
=

For amphiprotic species

$p H$ = $\frac{p K_{1} + p K_{2}}{2}$

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