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Question

pH of 0.05 M (CH3COO)2Ca (pKa=4.74) is -

A
8.72
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B
8.87
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C
7
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D
1.3
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Solution

The correct option is B 8.87
[CH3COO]=2×0.05=0.1

pH=12[pKw+pKa+logC]


=12[14+4.74+log 0.1]


=12[14+4.741]=8.87

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