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Types of Amino Acids

pH of 0.1 M ...

Question

$p H$ of 0.1 M $N a_{2} H P O_{4}$ and 0.2 M $N a H_{2} p O_{4}$ are respectively: $(p K_{a} f o r H P O_{4} a r e 2.2, 7.2 a n d 12.0)$

A

4.7, 9.6

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B

9.6, 4.7

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C

4.7, 5.6

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D

5.6, 4.7

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Solution

The correct option is B 9.6, 4.7
Since ${N a}_{2} {H P O}_{4}$ is amphiprotic acid, so its $p H$ is average of successive $p k a^{s}$ values

$∴ p H o f {N a}_{2} {H P O}_{4} = \frac{p K_{12} + p K_{13}}{2} = \frac{7.2 + 12.0}{2} = 9.6$
$p H$ of ${N a H}_{2} {P O}_{4} = \frac{p K_{11} + p K_{12}}{2} = \frac{2.2 + 7.2}{2} = 4.7$
$p H$ of Amphiprotic acids do not depend on their concentration.

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