pH of 0.1 M weak acid solution is 4. What is the dissociation constant of the acid ?
PH=−log[H+];[H+]=10−PH=10−4M[H+]=√Ka×C;Ka=[H+]2C=(10−4)0.1=10−7
a weak acid HX has a dissociation constant 10^-5. the ph of 0.1M solution of this acid will be