$p H$ of $10^{- 6} N K O H$ solution is:

6

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0.6

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8

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0.8

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Solution

The correct option is D $8$
$K O H$ is a strong electrolyte. It completely dissociates in solution.
$K O H \to K^{+} + O H^{-}$

Hence, $[O H^{-}] = [K O H] = 10^{- 6} M$

$p O H = - l o g [O H]^{-} = - l o g 10^{- 6} = 6$

$p H = 14 - p O H = 14 - 6 = 8$

Hence, the $p H$ of $10^{- 6} N K O H$ solution is 8.

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