pH of 1M HA (weak acid) is 2. Hence, vant Hoff factor is____________.

1.2

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1.02

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1.1

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1.01

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Solution

The correct option is C 1.01
$p H o f H A = 3$

$- log [H A] = p H$

$- log [H A] = - 2$

$\Rightarrow [H A] = a n t i l o g [- 2] = 10^{- 2} M$

$H A \to H^{+} + A^{-}$

$10^{- 2} - α α . α$

$T o t a l n u m b e r o f m o l e s = 10^{- 2} - α + α + α = 10^{- 2} + α$

$V o l u m e h a l f f a c t o r = \frac{T o t a l m o l e s a f t e r d i s s o c i a t i o n}{T o t a l m o l e s o f b e f o r e d i s s o c i a t i o n}$

$i = \frac{10^{- 2} + α}{1}$

For weak acids $α = 1$

$i = 0.01 + 1 = 1.01$

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