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Question

pH of a 0.001M NaOH solution will be:

A
9
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B
3
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C
11
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D
12
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Solution

The correct option is C 11
[OH]=103
pOH=log[OH]=log[103]=3

pH+pOH=14
pH+3=14
pH=11
pH of 103M NaOH=11

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