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Question

pH of a buffer solution decreases by 0.02 units when 0.12g of acetic acid is added to 250mL of a buffer solution of a acetic acid and potassium acetate at 27oC. The buffer capacity of the solution is:

A
0.1
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B
10
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C
1
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D
0.4
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Solution

The correct option is D 0.4
Given change in pH=0.02
To 250ml of Buffer solution 0.12g of acetic acid is added.
To 1000ml of Buffer solution 0.12×1000250=0.48g of acetic acid is added
Now number of moles of acetic acid added 0.4860=8×103moles
We know that Buffer capacity =Numberofmolesofacidaddedto1ltsolutionChangeinPH
=8×1030.02=0.4

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