Question

$pH$ of a dilute solution of $HCl$ is $6.95$. Calculate molarity of $HCl$ solution.
$[{10}^{-6.95}=11.22\times {10}^{-8}{10}^{-7.05}=11.22\times {10}^{-8}]$

Answer 1

We have,

$pH=-\log \left[H^{+}\right]$

Given $pH=6.95$

$\therefore -\log \left[H^{+}\right]=6.95$

$\Rightarrow \left[H^{+}\right]={10}^{-6.95}=11.22\times {10}^{-8}$

$\therefore$ Molarity of $HCl$ solution= $11.22\times {10}^{-8}M$