$p H$ of a salt of strong base with weak acid

p H = \frac{1}{2} p K_{w} + \frac{1}{2} p K_{a} + \frac{1}{2} log C

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p H = \frac{1}{2} p K_{w} - \frac{1}{2} p K_{a} - \frac{1}{2} log C

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p H = \frac{1}{2} p K_{w} + \frac{1}{2} p K_{a} - \frac{1}{2} log C

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Solution

The correct option is A $p H = \frac{1}{2} p K_{w} - \frac{1}{2} p K_{a} - \frac{1}{2} log C$
pH is a salt of strong base with weak acid is

$p H = \frac{1}{2} p K_{w} - \frac{1}{2} p K_{a} - \frac{1}{2} l o g C$

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N a_{2} S

H_{2} S = 5.0 \times 10^{- 5} K_{2}

H_{2} S = 2.5 \times 10^{- 11}

K_{b} = 1 \times 10^{- 6}

K_{a} = 1 \times 10^{- 4}

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