pH of a solution at 250C is 2.5. On dilution, pH increased to 3.0. The number of times of dilution is:
A
10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
√10
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
50
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
√50
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B√10 pH=2.5 then [H+]=10−3+0.5=M1 pH=3 then [H+]=10−3+=M2 Let V1=x and the solution is dilute by n times then V2=nx M1V1=M2V2 10−3+0.5×x=10−3×nx n=10−3+0.510−3=100.5(or)√10