pH of a solution at 25∘C is 2. If the pH is to be doubled, then the hydronium ion concentration of the solution should be:
A
halved
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B
increased to 100 times
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C
doubled
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D
decreased to 100 times
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Solution
The correct option is C decreased to 100 times pH=−log[H+]=2. Thus [H+]=10−2. The pH is doubled from 2 to 4. [H+]=10−4. Thus the hydronium ion concentration should be decreased to 100 times.