$p H$ of a strong acid solution is 3. On dilution, its $p H$ changes to $5$ . How many times the dilution has taken place?

2 times

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100 times

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5/3 times

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this is not possible with dilution

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Solution

The correct option is C 100 times
$p H =$ power of $H^{\oplus}$ ion
$p H = - log [H^{+}]$
$p H = 3$ , $- log [H^{+}] = 10^{- 3}$
$p H$ change to $5$ , So $[H^{+}]_{f i n a l} = 10^{- 5}$
So, dilution is $100$ times has taken place.

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pH of a strong acid solution is 3. On dilution, its pH changes to 5. How many times the dilution has taken place?

The correct option is C 100 timespH=power of H⊕ ionpH=−log[H+]pH=3, −log[H+]=10−3pH change to 5 , So [H+]final=10−5So, dilution is 100 times has taken place.

$p H$ of a strong acid solution is 3. On dilution, its $p H$ changes to $5$ . How many times the dilution has taken place?

The correct option is C 100 times
$p H =$ power of $H^{\oplus}$ ion
$p H = - log [H^{+}]$
$p H = 3$ , $- log [H^{+}] = 10^{- 3}$
$p H$ change to $5$ , So $[H^{+}]_{f i n a l} = 10^{- 5}$
So, dilution is $100$ times has taken place.