$p H$ of an aqueous solution is 5.5. The hydroxyl ion concentrated in the solution would be:

10^{- 5.5} M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10^{- 7.5} M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

10^{- 8.5} M

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10^{8.5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $10^{- 8.5} M$
$p H + p O H = 14$
$p O H = 14 - 5.5 = 8.5 =$ $- l o g [O H^{-}]$
$[O H^{-}] = 10^{- 8.5}$

Suggest Corrections

Similar questions

K_{a}

2.0 \times 10^{- 5}

0.2 M

At $25^{\circ} C$ , the dissociation constant of a base BOH is $1.0 \times 10^{- 12}$ . The

concentration of Hydroxyl ions in 0.01 M aqueous solution of the base

would be

K_{a}

2.0 \times 10^{- 5}

0.2 M

1.0 \times 10^{- 8}

Join BYJU'S Learning Program