Question

Phase different between the instantaneous velocity and acceleration of particle executing SHM is

• A. zero
• B. $\frac{\pi }{2}$
• C. $\pi$
• D. $2\pi$

Answer 1

The correct option is B $\frac{\pi }{2}$

Let,

$y=A\sin wt$

$\frac{dy}{dt}=Aw\cos wt=Aw\sin (wt+\frac{\pi }{2})$

$acceleration=A{w}^2\sin wt$

the phase difference between instantaneous velocity and acceleration is $\frac{\pi }{2}$