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Question

PhCH2CH(Br)PhAlc.KOH−−−−−Product

How many products are possible?

A
1
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B
2
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C
3
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D
4
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Solution

The correct option is B 2
Two products are possible. They are as shown.
497376_243855_ans_e505d3456aef4b2ea4d7639c31043405.png

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