PhCH-CHCHO-CH3CH-CHCHOA 87

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Industrial Preparation of Ethanoic Acid

PhCH=CHCHO+CH...

Question

$P h C H = C H C H O + C H_{3} C H = C H C H O base - ---- \to E t O H, Δ (A) 87 %$ ; Product of this reaction is :

P h - (C H = C H)_{2} - C H O

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P h - (C H = C H)_{3} C H O

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P h - (C H = C H)_{4} C H O

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P h - C H = C H - C H = C H - C H_{3}

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Solution

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Similar questions

P h - C H = C H C H O + C H_{3} C H = C H C H O b a s e ⟶ E t O H, Δ (A)

C H_{3} C H = C H C H O \to C H_{3} C H = C H C O O H : Ammoniacal A g N O_{3}

C H_{3} C H = C H C H O \to C H_{3} C H = C H C H_{2} O H : K M n O_{4}

R - C H O \to R - C H_{2} O H : N a B H_{4}

C H_{3} C H_{2} C O C l \to C H_{3} C H_{2} C H O : H_{2}, P d / B a S O_{4}

{C H}_{3} C H = C H C H O

{C H}_{3} - C H = C H C O O H

C H_{3} C H = C H C H O

P h C H O + (C H_{3} C O)_{2} O N a (O A c)_{2} \to P h C H = C H C O_{2} H

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