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Question

PhCHO+(CH3CO)2OCH3COONa−−−−−−−−→ A HBr−−−→ B

The product B is :

A
PhCH=CHCH2Br
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B
PhCH(Br)CH2COOH
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C
PhCH2CH(Br)COOH
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D
PhCH=CHCOBr
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Solution

The correct option is B PhCH(Br)CH2COOH
Benzaldehyde and acetic anhydride condense in the presesnce of sodium acetate to form compound A, which is cinnamic acid.
This is a Perkin condensation reaction.

Perkin reaction is followed by Markovnikov's addition of HBr to form 3- bromo-3-phenylpropanoic acid.

PhCHO+(CH3CO)2OCH3COONa−−−−−−−PhCH=CAHCOOHHBr−−PhCHBrCBH2COOH

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