Phenol1.CHCl3/NaOH−−−−−−−−−−→2.H+Salicylaldehyde The above reaction is known as:
A
Gattermann reaction
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B
Sandmeyer reaction
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C
Perkin reaction
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D
Reimer-Tiemann reaction
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Solution
The correct option is D Reimer-Tiemann reaction When phenol is treated with chloroform in the presence of base, it forms salicylaldehyde. The reaction is known as Reimer-Tiemann reaction.