Phenol $Z n - ----- \to d i s t i l l a t i o n$ A $c o n c . H N O_{3} - ----------- \to c o n c . H_{2} S O_{4} a t 60 ° C$ B $Z n - --- \to N a O H$ C

In the above reactions, the compounds (A), (B) and (C) respectively are :

benzene, nitrobenzene and hydrazobenzene

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benzene, nitrobenzene and aniline

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benzene, dinitrobenzene and m-nitroaniline

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toulene, m-nitrobenzene and m-toulidine

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Solution

The correct option is A benzene, nitrobenzene and hydrazobenzene
Phenol on heating with zinc dust produces benzene. Benzene on treatment with nitrating mixture $(c o n c . H N O_{3} a n d H_{2} S O_{4})$ produces nitrobenzene. Nitrobenzene is partially reduced to hydrazobenzene using $Z n - N a O H$ .
The reactions are as follows:
$P h O H Z n - d i s t i l l a t i o n - -------- \to P h H$
$P h H c o n c . H_{2} S O_{4} a t 60^{o} - ---------- \to c o n c . H N O_{3} P h - N O_{2}$
$P h - N O_{2} Z n - N a O H - ------ \to P h - N H - N H - P h$

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Phenol Zn−−−−−−→distillationA conc.HNO3−−−−−−−−−−−−→conc.H2SO4at60°CB Zn−−−−→NaOH CIn the above reactions, the compounds (A), (B) and (C) respectively are :

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