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Question

ϕ is an acute angle such that tanϕ=23 then evaluate (1+tanϕsinϕ+cosϕ)(1cotϕsecϕ+cosecϕ)

A
15
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B
413
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C
15
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D
413
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Solution

The correct option is B 15
=⎜ ⎜ ⎜ ⎜1+23213+313⎟ ⎟ ⎟ ⎟⎜ ⎜ ⎜ ⎜132133+132⎟ ⎟ ⎟ ⎟= \displaystyle\left(\displaystyle\frac{\displaystyle\frac{5}{3}}{\displaystyle\frac{5}{\sqrt {13}}}\right) \displaystyle\left(\displaystyle\frac{\displaystyle\frac{-1}{2}}{\displaystyle\frac{5\sqrt {13}}{6}}\right)$
=133×(12)×6513=15

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