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Standard XII

Chemistry

Ores and Minerals

Philosopher w...

Question

Philosopher wool is:

Z n O

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Z n S

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Z n O_{2}

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Z n S O_{4}

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Solution

The correct option is A $Z n O$
Philosopher wool: ZnO
Zinc blende: ZnS
Zinc peroxide: $Z n O_{2}$
Zinc sulphate $Z n S O_{4}$

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Similar questions

The major products of the following reaction

$Z n S (s) + O_{2} (g) h e a t - --- \to$

Are

The chief ore of

Z n

is the sulphide,

Z n S

. The ore is concentrated by froth floatation process and then heated in air to convert

Z n S

Z n O

2 Z n S + 3 O_{2} \to 2 Z n O + 2 S O_{2}

(

75 %

conversion)

Z n O + H_{2} S O_{4} \to Z n S O_{4} + H_{2} O

(

100 %

conversion )

2 Z n S O_{4} + 2 H_{2} O \to 2 Z n + 2 H_{2} S O_{4} + O_{2}

(

80 %

conversion)

The mass of

Z n

obtained from a sample of ore containing

292.2

kg of

Z n S

will be :

(A), (B), (C), (D), (E) and (F) base on the reactions are

A :

Z n S

B :

H_{2} S

C :

{Z n S O}_{4}

D :

P b S

E :

{Z n (O H)}_{2}

F :

{N a}_{2} {Z n O}_{2}

{N a}_{2} [{Z n (O H)}_{4}]

If the given statement is true enter 1, else enter 0.

Q. The chief ore of

Z n

is its sulphide,

Z n S

. The ore is concentrated by froth floatation process and then heated in air to convert

Z n S

Z n O

. The following reactions take place in the extraction of

Z n

2ZnS+3O2→2ZnO+2SO2 (Yield: 62.5 \%)

ZnO+H2SO4→ZnSO4+H2O (Yield: 80 \%)

2ZnSO4+2H2O→2Zn+2H2SO4+O2 (Yield: 80\%)

The number of moles of

Z n S

required for producing

2

mol of

Z n

will be:

Z n S O_{4} .7 H_{2} O A b o v e 39^{\circ} C - ------ \to B e l o w 70^{\circ} C A A b o v e 70^{\circ} C - ------ \to B A b o v e 280^{\circ} C - ------ \to O_{2} + S O_{2} + Z n O

. A and B respectively are:

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Philosopher wool is:

The correct option is A ZnOPhilosopher wool: ZnOZinc blende: ZnSZinc peroxide: ZnO2Zinc sulphate ZnSO4

The correct option is A $Z n O$
Philosopher wool: ZnO
Zinc blende: ZnS
Zinc peroxide: $Z n O_{2}$
Zinc sulphate $Z n S O_{4}$