Question

$PhN{H}_2$ and $PhNHMe$ can be differentiated by:

• A. $CHC{l}_3,KOH$
• B. $NaN{O}_2,HCl$
• C. Both (a) and (b)
• D. None of thses

Answer 1

The correct option is C Both (a) and (b)

$1^o$ amines and $2^o$ amines can be distinguished by both isocyanide test and diazotisation.
$PhN{H}_2$ is $1^o$ amine and gives +ve isocyanide test producing an unpleasant smell while $PhNHMe$ does not.
$PhN{H}_2+CHC{l}_3+KOH\to PhNC+3KCl+3H_{2}O$

$PhN{H}_2+NaN{O}_2+HCl\to Ph{N}_2^{+}+C{l}^{–}$
$PhNHMe+NaN{O}_2+HCl\to \underset{\text{(yellow oil)}}{Ph-\underset{NO}{\underset{|}{N}}-Me}$