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Question

Phosphine (PH3) decomposes to produce P4(g) and H2(g). What would be the change in volume when 100 mL of PH3(g) is completely decomposed?

A
50 mL
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B
500 mL
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C
75 mL
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D
250 mL
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Solution

The correct option is C 75 mL
The decomposition of PH3 takes place as,
4PH3P4+6H2

From the balanced equation,
4 mol of PH3 produces 6 mol of H2
and 1 mol of P4

So in terms of volume,
4 ml of PH3 produces 6 ml H2 and 1 ml P4

So, when 100 ml of PH3 decomposes, volume of the products will be, 64×100=150 ml
So the required change in volume is =150100 ml=50 ml


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