Phosphine (PH3) decomposes to produce P4(g) and H2(g). What would be the change in volume when 100mL of PH3(g) is completely decomposed? 4PH3(g)→P4(g)+6H2(g)
A
50mL
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B
500mL
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C
75mL
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D
250mL
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Solution
The correct option is C75mL 4PH3(g)→P4(g)+6H2(g)4vol.→1vol.6vol.100mL→100464×100100mL→25mL150mL
Change in volume =(150+25)–100=75mL
Volume will increase by 75mL since initially, only PH3(100mL) was present. After reaction P4(g) and H2(g) were formed which increased the volume.