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Question

Phosphine (PH3) decomposes to produce P4(g) and H2(g). What would be the change in volume when 100 mL of PH3(g) is completely decomposed?
4PH3(g)P4(g)+6H2(g)

A
50 mL
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B
500 mL
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C
75 mL
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D
250 mL
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Solution

The correct option is C 75 mL
4PH3(g)P4(g)+6H2(g)4 vol.1 vol.6 vol.100 mL100464×100100 mL25 mL150 mL

Change in volume =(150+25)100=75 mL
Volume will increase by 75 mL since initially, only PH3(100 mL) was present. After reaction P4(g) and H2(g) were formed which increased the volume.

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