Phosphoric acid is prepared in a two-step process. Find the mass of H3PO4 formed when 124 g of P4 reacts with an excess of oxygen and then treated with sufficient water. P4+O2⟶P4O10 P4O10+H2O⟶H3PO4
(Molar mass of P = 31 g/mol)
A
150 g
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B
288 g
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C
560 g
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D
392 g
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Solution
The correct option is D 392 g Let the weight of acid produced be Xg.
Since the atoms of P are conserved,
Applying POAC on phosphorus, 4×moles ofP4=1×moles ofH3PO4
⇒4×weight ofP4molar mass ofP4=1×weight of acidmolar mass of acid
⇒4×124124=1×X98
On solving, X=392g
Therefore,the mass of phosphoric acid produced is 392 g.