Photoelectric emission occurs only when incident light has more than certain minimum

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Solution

The correct option is C frequency
For emission to take place
$h v \geq ϕ$
$v \geq \frac{ϕ}{h}$
$v_{m i n} = \frac{ϕ}{h}$

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The threshold frequency for a certain metal is 3.3 × 10¹⁴Hz. If light of frequency 8.2 × 10¹⁴ Hz is incident on the metal, predict the cutoff voltage for the photoelectric emission.

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Photoelectric emission occurs only when incident light has more than certain minimum

The correct option is C frequency For emission to take place hv≥ϕ v≥ϕh vmin=ϕh

The correct option is C frequency
For emission to take place
$h v \geq ϕ$
$v \geq \frac{ϕ}{h}$
$v_{m i n} = \frac{ϕ}{h}$