Photon of energy $6 e V$ is incident on a metal surface of work function $4 e V$ . Maximum $K E$ of emitted photo-electrons will be :

0 e V

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1 e V

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2 e V

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10 e V

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Solution

The correct option is C $2 e V$
Given,
Energy of photon = $6 e V$
Work function = $4 e V$
Kinetic Energy = energy of photon - work function
$K E = 6 - 4 = 2 e V$

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