wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Photons of energy 6 eV are incident on a metal surface whose work function is 4 eV. The minimum kinetic energy of the emitted photo-electrons will be

A

0 eV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

1 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

2 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

10 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

Step 1, Given data

Energy of photon = 6 eV

Work function = 4 eV

Step 2, Finding the minimum energy of the emitted electron

We know,

Work function is the minimum energy that is required to make the electron come out of the surface.

So,

The energy of the emitted electron = Energy of the photon - Work function

So, Energy of the emitted electron = 6 eV - 4 eV = 2 eV

Hence the minimum energy of the emitted electron is 2 eV.



flag
Suggest Corrections
thumbs-up
7
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The Photon Theory
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon