photons with energy 5 eV are incident on a cathode C in photoelectric is 2 eV when photons of energy 6 eV are incident on V no photoelectrons will reach the anode A,if the stopping potential of A
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Solution
energy of 5 ev maximum energy of emitted photoelectrons is therefore einstein photoelectric energy relation is
ϕ=kmax−Ep
ϕ=5−2=3eV
photon energy 6ev are incident no photon electrons emitted