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Question

photons with energy 5 eV are incident on a cathode C in photoelectric is 2 eV when photons of energy 6 eV are incident on V no photoelectrons will reach the anode A,if the stopping potential of A

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Solution

energy of 5 ev maximum energy of emitted photoelectrons is therefore einstein photoelectric energy relation is
ϕ=kmaxEp
ϕ=52=3eV
photon energy 6ev are incident no photon electrons emitted
eV0=Epϕ=63=3ev
V0=3
strong potential of 3v has applied
it is different in negative potential 3

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