Question

Pick out the isoelectronic structures from the following.
(I) $C{H}_3^{+}$
(II) $H_3{O}^{+}$
(III) $N{H}_3$
(IV) $C{H}_3^{-}$

• A. I and II
• B. III and IV
• C. I and III
• D. II, III, IV

Answer 1

The correct option is D II, III, IV

$C{H}_3^{+}$ has $6+3-1=8$ electrons

$H_3{O}^{+}$ has $3+8-1=10$ electrons

$N{H}_3$ has $7+3=10$ electrons.

$C{H}_3^{-}$ has $6+3+1=10$ electrons

So, $II,III,IV$ are isoelectronic structures as they have the same number of electrons.

Hence, the correct option is $D$