The correct option is A P-2, Q-1, R-3, S-4
i) HCl+NaOH⟶NaCl(P)+H2O
Here limiting reagent is HCl.
Moles of (P) i.e. NaCl formed=20 ml×1 M=20 mmol
Molarity=mmolTotal vol.=2050=25 M
ii) Na2CO3(Q)+2HCl⟶2NaCl(R)+H2O
Moles of (Q) i.e. Na2CO3 present=20 ml×1 M=20 mmol
Moles of HCl present=30 ml×1 M=30 mmol
Here HCl is limiting reagent.
Moles of (R) i.e. NaCl formed=30 mmol
Molarity=mmolTotal vol.=3050=35 M
Moles of (Q) unreacted=5 mmol
Molarity of Q=550=110 M
Normality of Q=210=15 N
iii) NaHCO3(S) + HCl⟶NaCl+H2O+CO2
Molarity of S=1 M