Question

Pick the solutions from the values given in the bracket next to the equation. Show that the other values do not satisfy the equation:

$x+7=3(3,4,-4,-7)$

Answer 1

Given, equation is $x+7=3$

So, for $x=3$

we get, LHS$$\begin{gathered} =3+7 \\ =10 \end{gathered}$$

So, LHS$\ne$RHS, $x=3$ is not a solution for equation $x+7=3$

So, for $x=4$

we get, LHS$$\begin{gathered} =4+7 \\ =11 \end{gathered}$$

So, LHS$\ne$RHS, $x=4$ is not a solution for equation $x+7=3$

So, for $x=-4$

we get, LHS$$\begin{gathered} =-4+7 \\ =3 \end{gathered}$$

So, LHS$=$RHS, $x=-4$ is a solution for equation $x+7=3$

So, for $x=-7$

we get, LHS$$\begin{gathered} =-7+7 \\ =0 \end{gathered}$$

So, LHS$\ne$RHS, $x=-7$ is not a solution for equation $x+7=3$

Hence $x=-4$is a solution for equation $x+7=3$