Question

Pinky says that zeroes of $p\left(x\right)=x^3-1$ are $1,1,1$ and Sai Teja says that one of the zeroes is $1$, remaining two zeroes are not real, to whom do you support ? Give reason.

Answer 1

Given that $p\left(x\right)=x^3-1$

For zeroes of p(x)

$p\left(x\right)=0$

$x^3-1=0$

$x^3=1$

$x=1$

$x=1,1,1$

Hence we will support to pinky because roots of given polynomial will be real ,positive and similar like 1,1,1