Pinky spent 3/5of her money on a dress and a belt. The hand bag costs twice as much as the dress. The dress costs Rs20 more than the belt. How much money did she have in the begning

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Solution

Dear student,

$L e t t h e m o n e y s h e h a s i n t h e b e g i n i n g i s R s x M o n e y s p e n t o n d e s s a n d b e l t = R s \frac{3 x}{5} \Rightarrow C o s t o f d r e s s + C o s t o f b e l t = \frac{3 x}{5} - - (1) C o s t o f d r e s s = 20 + C os t o f b e l t \Rightarrow C o s t o f d r e s s - C o s t o f b e l t = 20 - - (2) s o l v i n g (1) a n d (2) C o s t o f d r e s s + C o s t o f b e l t = \frac{3 x}{5} C o s t o f d r e s s - C o s t o f b e l t = 20 2 C o s t o f d r e s s = \frac{3 x}{5} + 20 \Rightarrow C o s t o f d r e s s = \frac{3 x}{5 \times 2} + \frac{20}{2} = \frac{3 x}{10} + 10 a l s o \cos t o f h a n d b a g = 2 \times \cos t o f d r e s s = 2 \times (\frac{3 x}{10} + 10) \Rightarrow \cos t o f h a n d b a g = \frac{6 x}{10} + 20 M o n e y i n t h e b e g i n i n g = C o s t o f d r e s s + C o s t o f b e l t + C os t o f h a n d b a g \Rightarrow x = \frac{3 x}{5} + \frac{6 x}{10} + 20 \Rightarrow x = \frac{6 x + 6 x + 200}{10} \Rightarrow 10 x = 12 x + 200 \Rightarrow 10 x - 12 x = 200 \Rightarrow - 2 x = 200 \Rightarrow x = - 100 n e g l e c t i n g - v e s i g n s w e g e t x = R s 100 t h u e t h e m o n e y s h e h a s i n t h e b e g i n i n g i s R s 100$

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