Pipe $A$ can fill one fourth of a tank in $5$ hours and pipe $B$ can empty the full tank in $30$ hours.If both pipes are opened simultaneously, then in how many hours will the empty tank be filled.

10

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60

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25

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45

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Solution

The correct option is A $60$
Pipe can do $\frac{1}{4}$ work in 5 hours.
$\Rightarrow$ pipe can do $\frac{1}{20}$ work in 1 hours.
when both are opened simultaneously,
they can do $\frac{1}{20} \frac{- 1}{30} = \frac{1}{60}$ work in 1 hours
So, when opened together,
it takes 60 hours to fill the tank.

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Pipe A can fill one fourth of a tank in 5 hours and pipe B can empty the full tank in 30 hours.If both pipes are opened simultaneously, then in how many hours will the empty tank be filled.

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Pipe $A$ can fill one fourth of a tank in $5$ hours and pipe $B$ can empty the full tank in $30$ hours.If both pipes are opened simultaneously, then in how many hours will the empty tank be filled.