Pipe A can fill the tank 3 times faster in comparison to pipe B. It takes 36 minutes for pipe A and B to fill the tank together. How much time will pipe B alone take to fill the tank? [2 Marks]

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Solution

Let the time taken by pipe B be x minutes [0.5 Mark]

So, the time taken by pipe A = x/3 minutes [0.5 Mark]

Thus, 1/3 + 3/x = 1/36

⇒ 4/x = 1/36 [0.5 Mark]

⇒ x = 4×36

⇒ x = 144 minutes [0.5 Mark]

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Pipe A can fill the tank 3 times faster in comparison to pipe B. It takes 36 minutes for pipe A and B to fill the tank together. How much time will pipe B alone take to fill the tank? [2 Marks]

Let the time taken by pipe B be x minutes [0.5 Mark] So, the time taken by pipe A = x/3 minutes [0.5 Mark] Thus, 1/3 + 3/x = 1/36 ⇒ 4/x = 1/36 [0.5 Mark] ⇒ x = 4×36 ⇒ x = 144 minutes [0.5 Mark]

Let the time taken by pipe B be x minutes [0.5 Mark]

So, the time taken by pipe A = x/3 minutes [0.5 Mark]

Thus, 1/3 + 3/x = 1/36

⇒ 4/x = 1/36 [0.5 Mark]

⇒ x = 4×36

⇒ x = 144 minutes [0.5 Mark]