wiz-icon
MyQuestionIcon
MyQuestionIcon
8
You visited us 8 times! Enjoying our articles? Unlock Full Access!
Question

Piston cylinder device initially contains 0.5m3 of nitrogen gas at 400kPa and 27C. An electric heater within the device is turned on and is allowed to pass a current of 2A for 5min from a 120V source. Nitrogen expands at constant pressure and a heat loss of 2800J occurs during the process. R=253kJ/kmolK . The final temperature of nitrogen is

A
2.6C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
56.6C
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
29.6C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5.67C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 56.6C
Gas is nitrogen hence diatomicCp=7/2R
Given initial temperature =T0=300K, Initial pressure =P0=400kPa, Initial volume=V0=0.5m3
Applying ideal gas equation, number of moles, n=P0V0/RT=400×0.525/3×300=.08kmol=80mol
Heat supplied =2×5×60×120=72000J=72kJ
Also heat released =2.8 kJ
Net heat absorbed = heat supplied-heat released =nCpΔT=6920080×7/2×25/3×ΔT=69200
ΔT=29.6KT=329.6K
Hence, final temperature is 56.6 degrees.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
The First Law of Thermodynamics
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon