Question

Piston of cross-sectional area $100c{m}^2$ is used in a hydraulic pressure to exert a force of ${10}^7$ dyne on $A_1=100c{m}^2$. The cross-sectional area of the other piston supports a truck of mass 200 Kg is,

• A. $0.96c{m}^2$
• B. $0.196m^2$
• C. $0.98m^2$
• D. $98m^2$

Answer 1

The correct option is B. $0.196m^2$

Given that,

$A_1=100c{m}^2=0.01m^2$

$F_1={10}^{7}dyne={10}^{2}N$

$m=200Kg$

$A_2=?$

Using the relation as:

$\frac{F_1}{A_1}=\frac{F_2}{A_2}$

$\frac{100}{0.01}=\frac{mg}{A_2}$

$\frac{100}{0.01}=\frac{200\times 9.8}{A_2}$

$A_2=0.196m^2$.