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Basic Buffer Action

pKa1 of carbo...

Question

$p K_{a_{1}}$ of carbonic acid in blood at body temperature ( $37^{o} C$ ) is 6.1. Hence, ratio $[H C O_{3}^{-}] / [H_{2} C O_{3}]$ is approximately:

1.3 : 1

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1 : 1.3

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20 : 1

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1 : 20

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Solution

The correct option is B 20 : 1
$p H = p K_{a} + log [\frac{[H C O_{3}^{-}]}{H_{2} C O_{3}]}]$
$7.4 = 6.1 + log [\frac{[H C O_{3}^{-}]}{H_{2} C O_{3}]}]$
$log [\frac{[H C O_{3}^{-}]}{H_{2} C O_{3}]}] = 1.3$
$\frac{[H C O_{3}^{-}]}{[H_{2} C O_{3}]} = \frac{19.95}{1}$

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