MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Salt of Weak Acid and Strong Base

pK a of CH 3 ...

Question

$p K_{a}$ of $C H_{3} C O O H$ is 4.74. The pH of 0.01 M $C H_{3} C O O N a$ is

A

4.74

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

8.37

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

9.48

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 8.37
Given, $p K_{a} = 4.74$ $[C H_{3} C O O N a] = 0.01 M$
$C H_{3} C O O N a$ is a salt of a weak acid and strong base
$∴ p H = 7 + \frac{1}{2} [p K_{a} + l o g C]$
$p H = 7 + \frac{1}{2} [4.74 + l o g 0.01]$
$p H = 7 + \frac{1}{2} [4.74 - 2] = 8.37$

Suggest Corrections

thumbs-up

0

Similar questions

p H

of the solution containing equimolar amount of

C H_{3} C O O H

(p K_{a} = 4.74) and C H_{3} C O O^{-}

50^{\circ} C

p K_{a}

C H_{3} C O O H

is 4.74. The pH of 0.01 M

C H_{3} C O O N a

p K_{a}

C H_{3} C O O H

is 4.74. Thus, the buffer range for

C H_{3} C O O H

C H_{3} C O O N a

50 m L

0.1 M C H_{3} C O O N a (a q)

is titrated against a

0.1 M H C l (a q)

. Calculate the

p H

of solution when

50 m L H C l

was added.
Given:

p K_{a} (C H_{3} C O O H) = 4.74 a t 25^{o} C

Q. The pH of 1 M

C H_{3} C O O N a

solution in water will be nearly:

(p K_{a} f o r C H_{3} C O O H = 4.74)

View More

Join BYJU'S Learning Program

explore_more_icon

Explore more

Salt of Weak Acid and Strong Base

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon