pKb of NH3 is 4.74. The pH when 100 mL of 0.01 M NH3 solution is 50% neutralised by 0.01 M HCl is,
A
4.74
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B
2.37
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C
9.26
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D
9.48
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Solution
The correct option is C 9.26 At 50% neutralisation, [NH+4]=[NH3] The solution is a buffer ∴pOH=pKb+log[NH+4][NH3] = 4.74 + log 1 = 4.74 pH = 14 - 4.74 = 9.26