pKb of fluoride ions at $25$ deg celcius is $10.83$ , the ionisation const of hydrofluoric acid in water at this temp. is?

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Solution

$P K_{b} = 10.83$ $K_{b} = 10^{-} 10.83 = 1.48 \times 10^{-} 11$
$H F + H_{2} O = F^{-} + H_{3} O^{+}$
$K_{a} \times K_{B} = K_{w}$
$K_{a} = K_{w} / K_{b} = 10^{-} 14 / 1.48 \times 10^{-} 4$
$= 6.76 \times 10^{-} 4$

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