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Normality

pKIn nbsp;o...

Question

pK_In of the indicator(behaving as weak acid) is 10. At the equivalence point pH is
A. 5 B. 10 C. 7.5 D. 7

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Solution

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100

0.20 M

H A

0.20 M

N a O H

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N a O H

k_{a} = 4 \times 10^{- 5}

25^{\circ} C .

100 m L

0.20 M

H A

0.20 M

N a O H

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\frac{2}{15} M H C l

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(K_{w} = 1 \times 10^{- 14} a t 25^{\circ} C)

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pKIn of the indicator(behaving as weak acid) is 10. At the equivalence point pH is A. 5 B. 10 C. 7.5 D. 7